Bill Chun Wai Hung

Lab 7 Prelab

Q1)

Input 1	Input 2	AND gate Output	LED Output
0	0	0	1
0	1	0	0
1	0	0	0
1	1	1	0

Q2)

V1=V(0)=5V

V2=0V

I = 20mA

R=170 ohm

Q3)

Yes, the current changes. The resistance of the diode and Rs are in parallel, so the resistance is halved, while the R remains constant.

Q4)

Vin = A sin(wt)

Vc2=Vc3=A/2

In figure 3, at the point of the cursor, Vc2=Vc3=7.5V. The Amplitude of the input voltage is about 15V. The Vc2 and Vc3 are half the value of the input Vin.